What is the general solution for 2cos^2(t)-7cos(t)+5=0 ?

The general solution for 2cos^2(t)-7cos(t)+5=0 is t=2pin

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2cos^2(t)-7cos(t)+5=0

2 cos^{2} (t) - 7 cos (t) + 5 = 0

t = 2 πn

Solution steps

2 cos^{2} (t) - 7 cos (t) + 5 = 0

Solve by substitution

cos (t) = \frac{5}{2}, cos (t) = 1

cos (t) = \frac{5}{2} :

No Solution

cos (t) = 1 : t = 2 πn

Combine all the solutions

t = 2 πn

(cos (x)) = 0

arccos (x) = \frac{3}{8}

2 sin^{2} (θ) - 3 sin (θ) = 0

\frac{cos ( x )}{1 + sin ( x )} + tan (x) = cos (x)

sin (2 x) = 2 cos^{2} (x), 0 \leq x \leq 2 π

What is the general solution for 2cos^2(t)-7cos(t)+5=0 ?
The general solution for 2cos^2(t)-7cos(t)+5=0 is t=2pin