What is the general solution for 3cos(θ)=3sin(-θ) ?

The general solution for 3cos(θ)=3sin(-θ) is θ=(3pi)/4+pin

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3cos(θ)=3sin(-θ)

3 cos (θ) = 3 sin (- θ)

θ = \frac{3 π}{4} + πn

Solution steps

3 cos (θ) = 3 sin (- θ)

Rewrite using trig identities

3 cos (θ) = - 3 sin (θ)

Subtract

- 3 sin (θ)

from both sides

3 cos (θ) + 3 sin (θ) = 0

Rewrite using trig identities

3 + 3 tan (θ) = 0

Move

3

to the right side

3 tan (θ) = - 3

Divide both sides by

3

tan (θ) = - 1

General solutions for

tan (θ) = - 1

θ = \frac{3 π}{4} + πn

3 tan (\frac{2 x}{3}) + 1 = 0

sin (x) = \frac{11}{61}

sin^{3} (x) = - sin^{2} (x)

cos (θ) = \frac{4}{5}, sin (θ)

3 cos (2 θ) - 3 cos (θ) + 3 = 4 cos (θ) + 10

What is the general solution for 3cos(θ)=3sin(-θ) ?
The general solution for 3cos(θ)=3sin(-θ) is θ=(3pi)/4+pin