What is the general solution for 0=-4sin(2x) ?

The general solution for 0=-4sin(2x) is x=pin,x= pi/2+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0=-4sin(2x)

0 = - 4 sin (2 x)

x = πn, x = \frac{π}{2} + πn

Solution steps

0 = - 4 sin (2 x)

Switch sides

- 4 sin (2 x) = 0

Divide both sides by

- 4

sin (2 x) = 0

General solutions for

sin (2 x) = 0

2 x = 0 + 2 πn, 2 x = π + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

Solve

2 x = π + 2 πn : x = \frac{π}{2} + πn

x = πn, x = \frac{π}{2} + πn

cot (x) + 1 = 0, 0 \leq x < 2 π

x, cos (k x) = - 1

sec^{2} (x) = \frac{3}{4}

sin (x) = \frac{4.4 sin ( 11 9 ^{\circ} )}{12.3}

- sec^{2} (x) = 2 tan (x)

What is the general solution for 0=-4sin(2x) ?
The general solution for 0=-4sin(2x) is x=pin,x= pi/2+pin