What is the general solution for cos(θ)= 1/(sqrt(58)) ?

The general solution for cos(θ)= 1/(sqrt(58)) is θ=1.43910…+2pin,θ=2pi-1.43910…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(θ)= 1/(sqrt(58))

cos (θ) = \frac{1}{58}

θ = 1.43910 \dots + 2 πn, θ = 2 π - 1.43910 \dots + 2 πn

Solution steps

cos (θ) = \frac{1}{58}

Simplify

\frac{1}{58} : \frac{58}{58}

Apply trig inverse properties

θ = arccos (\frac{58}{58}) + 2 πn, θ = 2 π - arccos (\frac{58}{58}) + 2 πn

Show solutions in decimal form

θ = 1.43910 \dots + 2 πn, θ = 2 π - 1.43910 \dots + 2 πn

cos (4 x + 4) = sin (10 x + 44)

4 tan^{2} (x) - 3 sec^{2} (x) = 0

(sin (t) - 1) cos (t) = 0

csc (x) = 1, 0 \leq x \leq 2 π

4 sin (θ) + 33 = 3

What is the general solution for cos(θ)= 1/(sqrt(58)) ?
The general solution for cos(θ)= 1/(sqrt(58)) is θ=1.43910…+2pin,θ=2pi-1.43910…+2pin