What is the general solution for 2sin^2(θ)-11sin(θ)+9=0 ?

The general solution for 2sin^2(θ)-11sin(θ)+9=0 is θ= pi/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin^2(θ)-11sin(θ)+9=0

2 sin^{2} (θ) - 11 sin (θ) + 9 = 0

θ = \frac{π}{2} + 2 πn

Solution steps

2 sin^{2} (θ) - 11 sin (θ) + 9 = 0

Solve by substitution

sin (θ) = \frac{9}{2}, sin (θ) = 1

sin (θ) = \frac{9}{2} :

No Solution

sin (θ) = 1 : θ = \frac{π}{2} + 2 πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn

6 sin^{2} (4 x) - 4 = 0

tan (θ) + 3 = sec (θ)

sin (x) + cos (x) = csc (x)

5 sin (x) + 3 = 2

17 arccos (x) - 4 π = arccos (x)

What is the general solution for 2sin^2(θ)-11sin(θ)+9=0 ?
The general solution for 2sin^2(θ)-11sin(θ)+9=0 is θ= pi/2+2pin