What is the general solution for cos(θ)=-0.62 ?

The general solution for cos(θ)=-0.62 is θ=2.23953…+2pin,θ=-2.23953…+2pin

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cos(θ)=-0.62

cos (θ) = - 0.62

θ = 2.23953 \dots + 2 πn, θ = - 2.23953 \dots + 2 πn

Solution steps

cos (θ) = - 0.62

Apply trig inverse properties

θ = arccos (- 0.62) + 2 πn, θ = - arccos (- 0.62) + 2 πn

Show solutions in decimal form

θ = 2.23953 \dots + 2 πn, θ = - 2.23953 \dots + 2 πn

2 - 2 sin^{2} (x) = 2 cos^{2} (\frac{x}{2})

cos (4 x) sin (x) = 0

3 cos (3 θ) = 0

3 cot (\frac{π}{2} x) = - 3

0 = 3.46 sin (x) - 704.35

What is the general solution for cos(θ)=-0.62 ?
The general solution for cos(θ)=-0.62 is θ=2.23953…+2pin,θ=-2.23953…+2pin