What is the general solution for cos(4x)sin(x)=0 ?

The general solution for cos(4x)sin(x)=0 is x= pi/8+(pin)/2 ,x=(3pi)/8+(pin)/2 ,x=2pin,x=pi+2pin

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cos(4x)sin(x)=0

cos (4 x) sin (x) = 0

x = \frac{π}{8} + \frac{πn}{2}, x = \frac{3 π}{8} + \frac{πn}{2}, x = 2 πn, x = π + 2 πn

Solution steps

cos (4 x) sin (x) = 0

Solving each part separately

cos (4 x) = 0 or sin (x) = 0

cos (4 x) = 0 : x = \frac{π}{8} + \frac{πn}{2}, x = \frac{3 π}{8} + \frac{πn}{2}

sin (x) = 0 : x = 2 πn, x = π + 2 πn

Combine all the solutions

x = \frac{π}{8} + \frac{πn}{2}, x = \frac{3 π}{8} + \frac{πn}{2}, x = 2 πn, x = π + 2 πn

3 cos (3 θ) = 0

3 cot (\frac{π}{2} x) = - 3

0 = 3.46 sin (x) - 704.35

cos (θ) = \frac{3}{5}, \frac{3 π}{2} < θ < 2 π

cos (2 x) = \frac{3}{2}

What is the general solution for cos(4x)sin(x)=0 ?
The general solution for cos(4x)sin(x)=0 is x= pi/8+(pin)/2 ,x=(3pi)/8+(pin)/2 ,x=2pin,x=pi+2pin