What is the general solution for 2sin(x)4+3=0 ?

The general solution for 2sin(x)4+3=0 is x=-0.38439…+2pin,x=pi+0.38439…+2pin

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2sin(x)4+3=0

2 sin (x) 4 + 3 = 0

x = - 0.38439 \dots + 2 πn, x = π + 0.38439 \dots + 2 πn

Solution steps

2 sin (x) \cdot 4 + 3 = 0

Multiply the numbers:

2 \cdot 4 = 8

8 sin (x) + 3 = 0

Move

3

to the right side

8 sin (x) = - 3

Divide both sides by

8

sin (x) = - \frac{3}{8}

Apply trig inverse properties

x = arcsin (- \frac{3}{8}) + 2 πn, x = π + arcsin (\frac{3}{8}) + 2 πn

Show solutions in decimal form

x = - 0.38439 \dots + 2 πn, x = π + 0.38439 \dots + 2 πn

arctan (\frac{y}{- 1}) = 13 5^{\circ}

2 cos^{2} (x) + 3 cos (x) - 2 = 0, - π \leq x \leq π

- 5 cos (x) + 8.6602500000000 \dots sin (x) = - 5

sin (2 π \cdot 1.5 x) = 0

sin (15 x) + cos (15 x) = 0

What is the general solution for 2sin(x)4+3=0 ?
The general solution for 2sin(x)4+3=0 is x=-0.38439…+2pin,x=pi+0.38439…+2pin