What is the general solution for 3sin^2(θ)-8sin(θ)+5=0 ?

The general solution for 3sin^2(θ)-8sin(θ)+5=0 is θ= pi/2+2pin

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3sin^2(θ)-8sin(θ)+5=0

3 sin^{2} (θ) - 8 sin (θ) + 5 = 0

θ = \frac{π}{2} + 2 πn

Solution steps

3 sin^{2} (θ) - 8 sin (θ) + 5 = 0

Solve by substitution

sin (θ) = \frac{5}{3}, sin (θ) = 1

sin (θ) = \frac{5}{3} :

No Solution

sin (θ) = 1 : θ = \frac{π}{2} + 2 πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn

8 cos (x) - 4 = 0

sin^{2} (θ) = 5 sin (θ) + 6

2 = 2 sec (x)

cos (x) - sin (x) = \frac{2}{2}

cos^{2} (θ) = 1 + sin (θ)

What is the general solution for 3sin^2(θ)-8sin(θ)+5=0 ?
The general solution for 3sin^2(θ)-8sin(θ)+5=0 is θ= pi/2+2pin