What is the general solution for 2tan^2(θ)-tan(θ)=0 ?

The general solution for 2tan^2(θ)-tan(θ)=0 is θ=0.46364…+pin,θ=pin

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2tan^2(θ)-tan(θ)=0

2 tan^{2} (θ) - tan (θ) = 0

θ = 0.46364 \dots + πn, θ = πn

Solution steps

2 tan^{2} (θ) - tan (θ) = 0

Solve by substitution

tan (θ) = \frac{1}{2}, tan (θ) = 0

tan (θ) = \frac{1}{2} : θ = arctan (\frac{1}{2}) + πn

tan (θ) = 0 : θ = πn

Combine all the solutions

θ = arctan (\frac{1}{2}) + πn, θ = πn

Show solutions in decimal form

θ = 0.46364 \dots + πn, θ = πn

3 sin (θ) + 2 = 0

7 cos (2 θ) = 7 cos (θ)

csc (4 x) = - 1

cos (θ) = \frac{m ^{2} - n ^{2}}{m ^{2} + n ^{2}}

cos (θ) = \frac{6}{5}

What is the general solution for 2tan^2(θ)-tan(θ)=0 ?
The general solution for 2tan^2(θ)-tan(θ)=0 is θ=0.46364…+pin,θ=pin