What is the general solution for cos(2x)=-sin(2x) ?

The general solution for cos(2x)=-sin(2x) is x=(3pi)/8+(pin)/2

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cos(2x)=-sin(2x)

cos (2 x) = - sin (2 x)

x = \frac{3 π}{8} + \frac{πn}{2}

Solution steps

cos (2 x) = - sin (2 x)

Rewrite using trig identities

- tan (2 x) = 1

Divide both sides by

- 1

tan (2 x) = - 1

General solutions for

tan (2 x) = - 1

2 x = \frac{3 π}{4} + πn

Solve

2 x = \frac{3 π}{4} + πn : x = \frac{3 π}{8} + \frac{πn}{2}

x = \frac{3 π}{8} + \frac{πn}{2}

α, sin^{2} (α) + sin^{2} (β) = 1

- 6 cos (A) + 8 = 3 cos (A) + 8

cos (x) - 5 = - 4 - sin (x)

sin (d) = 0.19

2 sin^{2} (4 x) = 1

What is the general solution for cos(2x)=-sin(2x) ?
The general solution for cos(2x)=-sin(2x) is x=(3pi)/8+(pin)/2