What is the general solution for a/(sin(a))= a/(sin(B)) ?

The general solution for a/(sin(a))= a/(sin(B)) is B=arcsin(sin(a))+2pin,B=pi+arcsin(-sin(a))+2pin

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a/(sin(a))= a/(sin(B))

\frac{a}{sin ( a )} = \frac{a}{sin ( B )}

B = arcsin (sin (a)) + 2 πn, B = π + arcsin (- sin (a)) + 2 πn

Solution steps

\frac{a}{sin ( a )} = \frac{a}{sin ( B )}

Cross multiply

a sin (B) = sin (a) a

Divide both sides by

a; a \neq = 0

sin (B) = sin (a); sin (a) \neq = 0, a \neq = 0

Apply trig inverse properties

B = arcsin (sin (a)) + 2 πn, B = π + arcsin (- sin (a)) + 2 πn

cos (θ) = 1, 0^{\circ} \leq θ \leq 18 0^{\circ}

x, z = cos (2 x + y)

16 tan^{2} (x) - 1 = 0

sin^{2} (x) - sin (x) = 0, 0 \leq x \leq 2 π

sin (x + 3 7^{\circ}) = cos (2 x + 8)

What is the general solution for a/(sin(a))= a/(sin(B)) ?
The general solution for a/(sin(a))= a/(sin(B)) is B=arcsin(sin(a))+2pin,B=pi+arcsin(-sin(a))+2pin