What is the general solution for 1+2cot(θ)-2cot^2(θ)=-3cot^2(θ) ?

The general solution for 1+2cot(θ)-2cot^2(θ)=-3cot^2(θ) is θ=(3pi)/4+pin

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1+2cot(θ)-2cot^2(θ)=-3cot^2(θ)

1 + 2 cot (θ) - 2 cot^{2} (θ) = - 3 cot^{2} (θ)

θ = \frac{3 π}{4} + πn

Solution steps

1 + 2 cot (θ) - 2 cot^{2} (θ) = - 3 cot^{2} (θ)

Solve by substitution

cot (θ) = - 1

cot (θ) = - 1 : θ = \frac{3 π}{4} + πn

Combine all the solutions

θ = \frac{3 π}{4} + πn

3 arctan (2 x) = π

sin (x) - 9 = cos (x) - 9

7 sin (x) + 1 = 5 sin (x)

sec (x) + tan (x) = 1, (0, 2 π)

cos^{2} (θ) - cos (θ) - 20 = 0

What is the general solution for 1+2cot(θ)-2cot^2(θ)=-3cot^2(θ) ?
The general solution for 1+2cot(θ)-2cot^2(θ)=-3cot^2(θ) is θ=(3pi)/4+pin