What is the general solution for 2cos(x)-cos^2(x)=0 ?

The general solution for 2cos(x)-cos^2(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin

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2cos(x)-cos^2(x)=0

2 cos (x) - cos^{2} (x) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

2 cos (x) - cos^{2} (x) = 0

Solve by substitution

cos (x) = 0, cos (x) = 2

cos (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

cos (x) = 2 :

No Solution

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

- sec^{2} (x) - 5 = 2 sec (x) - 4

2 sin^{2} (x) + 2 sin (x) = 0

8 sin (x) cos (x) = 0

cos (θ) = \frac{9}{41}

3 cos (2 t) + 4 = 1, 0 \leq t \leq π

What is the general solution for 2cos(x)-cos^2(x)=0 ?
The general solution for 2cos(x)-cos^2(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin