Is csc^2(θ)-cos(θ)sec(θ)=cot^2(θ) ?

The answer to whether csc^2(θ)-cos(θ)sec(θ)=cot^2(θ) is True

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prove csc^2(θ)-cos(θ)sec(θ)=cot^2(θ)

prove

csc^{2} (θ) - cos (θ) sec (θ) = cot^{2} (θ)

True

Solution steps

csc^{2} (θ) - cos (θ) sec (θ) = cot^{2} (θ)

Manipulating left side

csc^{2} (θ) - cos (θ) sec (θ)

Rewrite using trig identities

= cot^{2} (θ)

We showed that the two sides could take the same form

\Rightarrow True

sin (x) + cos (x) = 1

8 cos^{2} (x) - 8 sin^{2} (x) = 8 - 16 sin^{2} (x)

\frac{sec ( x ) csc ( x )}{cot ( x )} = sec^{2} (x)

(sin (θ) - cos (θ))^{2} = 1 - 2 sin (θ) cos (θ)

cot (θ) sin (θ) sec (θ) = 1

Is csc^2(θ)-cos(θ)sec(θ)=cot^2(θ) ?
The answer to whether csc^2(θ)-cos(θ)sec(θ)=cot^2(θ) is True