Is 1/(sin^2(x))=1-tan^2(x) ?

The answer to whether 1/(sin^2(x))=1-tan^2(x) is False

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prove 1/(sin^2(x))=1-tan^2(x)

prove

\frac{1}{sin ^{2} ( x )} = 1 - tan^{2} (x)

False

Solution steps

\frac{1}{sin ^{2} ( x )} = 1 - tan^{2} (x)

Show that the two sides are not equal

For

\frac{1}{sin ^{2} ( x )} = 1 - tan^{2} (x)

plug in

x = 1

\frac{1}{sin ^{2} ( 1 )} = 1.41228 \dots

\frac{1}{sin ^{2} ( 1 )}

Refine to a decimal form

= 1.41228 \dots

1 - tan^{2} (1) = - 1.42551 \dots

1 - tan^{2} (1)

Refine to a decimal form

= - 1.42551 \dots

The two sides are not equal

\Rightarrow False

(\frac{1}{2 cot ( x ) ( 1 - cos ^{2} ( x ) )}) = 2 cot (x)

3 sec^{2} (x) - 4 = 0

sin (3 θ) = 3 sin (θ) - 4 sin (3 θ)

(sec^{2} (x) cot (x)) + cot (x) = tan (x)

cos (- \frac{1}{2}) = cos (\frac{2}{2})

Is 1/(sin^2(x))=1-tan^2(x) ?
The answer to whether 1/(sin^2(x))=1-tan^2(x) is False