What is the value of 3(cos(30))^2+2(sin(30))^2 ?

The value of 3(cos(30))^2+2(sin(30))^2 is 11/4

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Popular >

3(cos(30))^2+2(sin(30))^2

Solution

3 (cos (3 0^{\circ}))^{2} + 2 (sin (3 0^{\circ}))^{2}

Solution

\frac{11}{4}

Decimal Notation

2.75

Solution steps

3 (cos (3 0^{\circ}))^{2} + 2 (sin (3 0^{\circ}))^{2}

= 3 cos^{2} (3 0^{\circ}) + 2 sin^{2} (3 0^{\circ})

Use the following trivial identity:

cos (3 0^{\circ}) = \frac{3}{2}

cos (3 0^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{3}{2}

Use the following trivial identity:

sin (3 0^{\circ}) = \frac{1}{2}

sin (3 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

= 3 (\frac{3}{2})^{2} + 2 (\frac{1}{2})^{2}

Simplify

3 (\frac{3}{2})^{2} + 2 (\frac{1}{2})^{2} : \frac{11}{4}

3 (\frac{3}{2})^{2} + 2 (\frac{1}{2})^{2}

3 (\frac{3}{2})^{2} = \frac{9}{4}

3 (\frac{3}{2})^{2}

(\frac{3}{2})^{2} = \frac{3}{2 ^{2}}

(\frac{3}{2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 3 ) ^{2}}{2 ^{2}}

(3)^{2} : 3

Apply radical rule:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 3

= \frac{3}{2 ^{2}}

= 3 \cdot \frac{3}{2 ^{2}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 \cdot 3}{2 ^{2}}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{9}{2 ^{2}}

2^{2} = 4

= \frac{9}{4}

2 (\frac{1}{2})^{2} = \frac{1}{2}

2 (\frac{1}{2})^{2}

(\frac{1}{2})^{2} = \frac{1}{2 ^{2}}

(\frac{1}{2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{2 ^{2}}

Apply rule

1^{a} = 1

1^{2} = 1

= \frac{1}{2 ^{2}}

= 2 \cdot \frac{1}{2 ^{2}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2 ^{2}}

Multiply the numbers:

1 \cdot 2 = 2

= \frac{2}{2 ^{2}}

Cancel the common factor:

2

= \frac{1}{2}

= \frac{9}{4} + \frac{1}{2}

Least Common Multiplier of

4, 2 : 4

4, 2

Least Common Multiplier (LCM)

Prime factorization of

4 : 2 \cdot 2

4

4

divides by

24 = 2 \cdot 2

= 2 \cdot 2

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Multiply each factor the greatest number of times it occurs in either

4

2

= 2 \cdot 2

Multiply the numbers:

2 \cdot 2 = 4

= 4

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

4

For

\frac{1}{2} :

multiply the denominator and numerator by

2

\frac{1}{2} = \frac{1 \cdot 2}{2 \cdot 2} = \frac{2}{4}

= \frac{9}{4} + \frac{2}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{9 + 2}{4}

Add the numbers:

9 + 2 = 11

= \frac{11}{4}

= \frac{11}{4}

Popular Examples

0-6tan(30)+1/2*9.8*(6/(7.5*cos(30)))^2

0 - 6 tan (3 0^{\circ}) + \frac{1}{2} \cdot 9.8 \cdot (\frac{6}{7.5 \cdot cos ( 3 0 ^{\circ} )})^{2}

sec(42)

sec (4 2^{\circ})

(pi/3 cos(pi/3)-sin(pi/3))/((pi/3)^2)

\frac{\frac{π}{3} cos ( \frac{π}{3} ) - sin ( \frac{π}{3} )}{( \frac{π}{3} ) ^{2}}

arccos((sqrt(5))/2)

arccos (\frac{5}{2})

0.23*cos(62.2)

0.23 \cdot cos (62. 2^{\circ})

Frequently Asked Questions (FAQ)

What is the value of 3(cos(30))^2+2(sin(30))^2 ?
The value of 3(cos(30))^2+2(sin(30))^2 is 11/4