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Popular >

cosh(x)cosh(1)-sinh(x)sinh(1)=2

Solution

cosh (x) cosh (1) - sinh (x) sinh (1) = 2

Solution

x = ln (e (2 + 3)), x = ln (e (2 - 3))

+1

Solution steps

cosh (x) cosh (1) - sinh (x) sinh (1) = 2

Rewrite using trig identities

\frac{e ^{x} + e ^{- x}}{2} \cdot \frac{e ^{1} + e ^{- 1}}{2} - \frac{e ^{x} - e ^{- x}}{2} \cdot \frac{e ^{1} - e ^{- 1}}{2} = 2

\frac{e ^{x} + e ^{- x}}{2} \cdot \frac{e ^{1} + e ^{- 1}}{2} - \frac{e ^{x} - e ^{- x}}{2} \cdot \frac{e ^{1} - e ^{- 1}}{2} = 2 : x = ln (e (2 + 3)), x = ln (e (2 - 3))

x = ln (e (2 + 3)), x = ln (e (2 - 3))

Popular Examples

cos^2(x)=(3(1-sin(x)))/2

cos^{2} (x) = \frac{3 ( 1 - sin ( x ) )}{2}

2cos(θ)=2cos(3θ)

2 cos (θ) = 2 cos (3 θ)

cos(t)+cos(2t)=-0.75

cos (t) + cos (2 t) = - 0.75

9.8*sin(α)-1.96*cos(α)=0.47

9.8 \cdot sin (α) - 1.96 \cdot cos (α) = 0.47

1=(2-sin(x))/(sin^2(x))

1 = \frac{2 - sin ( x )}{sin ^{2} ( x )}

Frequently Asked Questions (FAQ)

What is the general solution for cosh(x)cosh(1)-sinh(x)sinh(1)=2 ?
The general solution for cosh(x)cosh(1)-sinh(x)sinh(1)=2 is x=ln(e(2+sqrt(3))),x=ln(e(2-sqrt(3)))