What is the general solution for 1=(2-sin(x))/(sin^2(x)) ?

The general solution for 1=(2-sin(x))/(sin^2(x)) is x= pi/2+2pin

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1=(2-sin(x))/(sin^2(x))

1 = \frac{2 - sin ( x )}{sin ^{2} ( x )}

x = \frac{π}{2} + 2 πn

Solution steps

1 = \frac{2 - sin ( x )}{sin ^{2} ( x )}

Switch sides

\frac{2 - sin ( x )}{sin ^{2} ( x )} = 1

Solve by substitution

sin (x) = 1, sin (x) = - 2

sin (x) = 1 : x = \frac{π}{2} + 2 πn

sin (x) = - 2 :

No Solution

Combine all the solutions

x = \frac{π}{2} + 2 πn

2 - 5 cos (x + 1) = 4

2 (tan (θ) + 3) = 5 + tan (θ)

sin^{2} (x) = \frac{( 9 m - 8 )}{2}

\frac{5}{2} cos (2 x) - \frac{1}{2} = 3 sin (x)

cos (π + x) = \frac{1}{2}

What is the general solution for 1=(2-sin(x))/(sin^2(x)) ?
The general solution for 1=(2-sin(x))/(sin^2(x)) is x= pi/2+2pin