What is the general solution for cos(θ/3+24)=sin(θ) ?

The general solution for cos(θ/3+24)=sin(θ) is θ=(1980+10800n)/(40),θ=(3420+10800n)/(20)

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cos(θ/3+24)=sin(θ)

cos (\frac{θ}{3} + 2 4^{\circ}) = sin (θ)

θ = \frac{198 0 ^{\circ} + 1080 0 ^{\circ} n}{40}, θ = \frac{342 0 ^{\circ} + 1080 0 ^{\circ} n}{20}

Solution steps

cos (\frac{θ}{3} + 2 4^{\circ}) = sin (θ)

Rewrite using trig identities

cos (\frac{θ}{3} + 2 4^{\circ}) = sin (9 0^{\circ} - (\frac{θ}{3} + 2 4^{\circ}))

Apply trig inverse properties

θ = 9 0^{\circ} - (\frac{θ}{3} + 2 4^{\circ}) + 36 0^{\circ} n, θ = 18 0^{\circ} - (9 0^{\circ} - (\frac{θ}{3} + 2 4^{\circ})) + 36 0^{\circ} n

θ = 9 0^{\circ} - (\frac{θ}{3} + 2 4^{\circ}) + 36 0^{\circ} n : θ = \frac{198 0 ^{\circ} + 1080 0 ^{\circ} n}{40}

θ = 18 0^{\circ} - (9 0^{\circ} - (\frac{θ}{3} + 2 4^{\circ})) + 36 0^{\circ} n : θ = \frac{342 0 ^{\circ} + 1080 0 ^{\circ} n}{20}

θ = \frac{198 0 ^{\circ} + 1080 0 ^{\circ} n}{40}, θ = \frac{342 0 ^{\circ} + 1080 0 ^{\circ} n}{20}

- 4 + 4 sin (x) = - 2

sin (x + π) + sin (x - π) = 0

cos (y) - sin (y) = 0

36 sin (x) cos (x) = - 93

sin (2 x) = cos (4 x)

What is the general solution for cos(θ/3+24)=sin(θ) ?
The general solution for cos(θ/3+24)=sin(θ) is θ=(1980+10800n)/(40),θ=(3420+10800n)/(20)