What is the general solution for 100=(50)(sqrt(40))cos(θ) ?

The general solution for 100=(50)(sqrt(40))cos(θ) is θ=1.24904…+2pin,θ=2pi-1.24904…+2pin

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100=(50)(sqrt(40))cos(θ)

100 = (50) (40) cos (θ)

θ = 1.24904 \dots + 2 πn, θ = 2 π - 1.24904 \dots + 2 πn

Solution steps

100 = (50) (40) cos (θ)

Switch sides

5040 cos (θ) = 100

Simplify

5040 : 10010

10010 cos (θ) = 100

Divide both sides by

10010

cos (θ) = \frac{10}{10}

Apply trig inverse properties

θ = arccos (\frac{10}{10}) + 2 πn, θ = 2 π - arccos (\frac{10}{10}) + 2 πn

Show solutions in decimal form

θ = 1.24904 \dots + 2 πn, θ = 2 π - 1.24904 \dots + 2 πn

cos (x) = a

cos (4 w) = 0

(2 sin (x) + 5) (3 cos (x) + 3) (tan^{2} (x) - 2) = 0

3 sin (x) + 3 cos (2 x) = 2

tan (3 x + 2 5^{\circ}) \cdot 16 0^{\circ} - 1 = 0

What is the general solution for 100=(50)(sqrt(40))cos(θ) ?
The general solution for 100=(50)(sqrt(40))cos(θ) is θ=1.24904…+2pin,θ=2pi-1.24904…+2pin