What is the general solution for (cos(x)-4)(cos(x)+1)=0 ?

The general solution for (cos(x)-4)(cos(x)+1)=0 is x=pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(cos(x)-4)(cos(x)+1)=0

(cos (x) - 4) (cos (x) + 1) = 0

x = π + 2 πn

Solution steps

(cos (x) - 4) (cos (x) + 1) = 0

Solving each part separately

cos (x) - 4 = 0 or cos (x) + 1 = 0

cos (x) - 4 = 0 :

No Solution

cos (x) + 1 = 0 : x = π + 2 πn

Combine all the solutions

x = π + 2 πn

- 15 + 4 cos (x) = - 15 - 22

tan^{2} (x) sin (x) = tan^{2} (x)

2 sin (θ) = 2, 0 \leq θ < 2 π

2 cos^{2} (t) - 3 cos (t) = - 1

cos (t) - cos (2 t) = - 0.75

What is the general solution for (cos(x)-4)(cos(x)+1)=0 ?
The general solution for (cos(x)-4)(cos(x)+1)=0 is x=pi+2pin