What is the general solution for 8cos(1/2 x)+4=0 ?

The general solution for 8cos(1/2 x)+4=0 is x=(4pi)/3+4pin,x=(8pi)/3+4pin

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8cos(1/2 x)+4=0

8 cos (\frac{1}{2} x) + 4 = 0

x = \frac{4 π}{3} + 4 πn, x = \frac{8 π}{3} + 4 πn

Solution steps

8 cos (\frac{1}{2} x) + 4 = 0

Move

4

to the right side

8 cos (\frac{1}{2} x) = - 4

Divide both sides by

8

cos (\frac{1}{2} x) = - \frac{1}{2}

General solutions for

cos (\frac{1}{2} x) = - \frac{1}{2}

\frac{1}{2} x = \frac{2 π}{3} + 2 πn, \frac{1}{2} x = \frac{4 π}{3} + 2 πn

Solve

\frac{1}{2} x = \frac{2 π}{3} + 2 πn : x = \frac{4 π}{3} + 4 πn

Solve

\frac{1}{2} x = \frac{4 π}{3} + 2 πn : x = \frac{8 π}{3} + 4 πn

x = \frac{4 π}{3} + 4 πn, x = \frac{8 π}{3} + 4 πn

5 sin (2 t) = 0

3 tan (3 x) + 3 = 0, 0^{\circ} \leq x \leq 18 0^{\circ}

2 tan (θ) + 4 = tan (θ) + 5

x, sin (x) = \frac{4}{5}

tan (x) = \frac{- 25}{\frac{- 80 - 50}{2}}

What is the general solution for 8cos(1/2 x)+4=0 ?
The general solution for 8cos(1/2 x)+4=0 is x=(4pi)/3+4pin,x=(8pi)/3+4pin