What is the general solution for tan(2θ)=-sqrt(3),0<= θ<= 360 ?

The general solution for tan(2θ)=-sqrt(3),0<= θ<= 360 is θ=60,θ=150,θ=240,θ=330

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tan(2θ)=-sqrt(3),0<= θ<= 360

tan (2 θ) = - 3, 0^{\circ} \leq θ \leq 36 0^{\circ}

θ = 6 0^{\circ}, θ = 15 0^{\circ}, θ = 24 0^{\circ}, θ = 33 0^{\circ}

Solution steps

tan (2 θ) = - 3, 0^{\circ} \leq θ \leq 36 0^{\circ}

General solutions for

tan (2 θ) = - 3

2 θ = 12 0^{\circ} + 18 0^{\circ} n

Solve

2 θ = 12 0^{\circ} + 18 0^{\circ} n : θ = 6 0^{\circ} + \frac{18 0 ^{\circ} n}{2}

θ = 6 0^{\circ} + \frac{18 0 ^{\circ} n}{2}

Solutions for the range

0 \leq θ \leq 36 0^{\circ}

θ = 6 0^{\circ}, θ = 15 0^{\circ}, θ = 24 0^{\circ}, θ = 33 0^{\circ}

0 = tan (c)

cos (t) - cos (2 t) = 0

4 sin (θ) = - 2 cos (θ)

cot (2 x) = - 1, (0, 2 π)

(sin (x) + 2) (tan (x) - 2) = 0

What is the general solution for tan(2θ)=-sqrt(3),0<= θ<= 360 ?
The general solution for tan(2θ)=-sqrt(3),0<= θ<= 360 is θ=60,θ=150,θ=240,θ=330