What is the general solution for cos(t)-cos(2t)=0 ?

The general solution for cos(t)-cos(2t)=0 is t=(4pin)/3 ,t=(2pi)/3+(4pin)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(t)-cos(2t)=0

cos (t) - cos (2 t) = 0

t = \frac{4 πn}{3}, t = \frac{2 π}{3} + \frac{4 πn}{3}

Solution steps

cos (t) - cos (2 t) = 0

Rewrite using trig identities

2 sin (\frac{3 t}{2}) sin (\frac{t}{2}) = 0

Solving each part separately

sin (\frac{3 t}{2}) = 0 or sin (\frac{t}{2}) = 0

sin (\frac{3 t}{2}) = 0 : t = \frac{4 πn}{3}, t = \frac{2 π}{3} + \frac{4 πn}{3}

sin (\frac{t}{2}) = 0 : t = 4 πn, t = 2 π + 4 πn

Combine all the solutions

t = \frac{4 πn}{3}, t = \frac{2 π}{3} + \frac{4 πn}{3}, t = 4 πn, t = 2 π + 4 πn

Merge Overlapping Intervals

t = \frac{4 πn}{3}, t = \frac{2 π}{3} + \frac{4 πn}{3}

4 sin (θ) = - 2 cos (θ)

cot (2 x) = - 1, (0, 2 π)

(sin (x) + 2) (tan (x) - 2) = 0

sec^{2} (x) + 4 sec (x) - 12 = 0

sin (θ) = - 1, 0^{\circ} \leq θ < 36 0^{\circ}

What is the general solution for cos(t)-cos(2t)=0 ?
The general solution for cos(t)-cos(2t)=0 is t=(4pin)/3 ,t=(2pi)/3+(4pin)/3