What is the general solution for tan^2(2θ)=1 ?

The general solution for tan^2(2θ)=1 is θ= pi/8+(pin)/2 ,θ=(3pi)/8+(pin)/2

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tan^2(2θ)=1

tan^{2} (2 θ) = 1

θ = \frac{π}{8} + \frac{πn}{2}, θ = \frac{3 π}{8} + \frac{πn}{2}

Solution steps

tan^{2} (2 θ) = 1

Solve by substitution

tan (2 θ) = 1, tan (2 θ) = - 1

tan (2 θ) = 1 : θ = \frac{π}{8} + \frac{πn}{2}

tan (2 θ) = - 1 : θ = \frac{3 π}{8} + \frac{πn}{2}

Combine all the solutions

θ = \frac{π}{8} + \frac{πn}{2}, θ = \frac{3 π}{8} + \frac{πn}{2}

(50.691) cos (50.69 1^{\circ} - c) + sin (50.69 1^{\circ} - c) = 0

sec (4 θ) = 2

tan^{2} (x) - 4 tan (x) + 1 = 0

sec (θ) + cos (θ) = sin (θ) tan (θ)

cos (x) = 0.98

What is the general solution for tan^2(2θ)=1 ?
The general solution for tan^2(2θ)=1 is θ= pi/8+(pin)/2 ,θ=(3pi)/8+(pin)/2