What is the general solution for cos(θ)=-9/10 ?

The general solution for cos(θ)=-9/10 is θ=2.69056…+2pin,θ=-2.69056…+2pin

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cos(θ)=-9/10

cos (θ) = - \frac{9}{10}

θ = 2.69056 \dots + 2 πn, θ = - 2.69056 \dots + 2 πn

Solution steps

cos (θ) = - \frac{9}{10}

Apply trig inverse properties

θ = arccos (- \frac{9}{10}) + 2 πn, θ = - arccos (- \frac{9}{10}) + 2 πn

Show solutions in decimal form

θ = 2.69056 \dots + 2 πn, θ = - 2.69056 \dots + 2 πn

arctan (x) = \frac{1}{2}

tan (2 θ) = 2

12 sin^{3} (x) - 9 sin (x) = 0

cos (3 0^{\circ} + x) - sin (x) = 0

53 cos (x) - 10 sin (x) cos (x) = 0

What is the general solution for cos(θ)=-9/10 ?
The general solution for cos(θ)=-9/10 is θ=2.69056…+2pin,θ=-2.69056…+2pin