What is the general solution for sin^2(θ)-2sin(θ)+3=0 ?

The general solution for sin^2(θ)-2sin(θ)+3=0 is No Solution for θ\in\mathbb{R}

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sin^2(θ)-2sin(θ)+3=0

sin^{2} (θ) - 2 sin (θ) + 3 = 0

No Solution for θ \in R

Solution steps

sin^{2} (θ) - 2 sin (θ) + 3 = 0

Solve by substitution

sin (θ) = 1 + 2 i, sin (θ) = 1 - 2 i

sin (θ) = 1 + 2 i :

No Solution

sin (θ) = 1 - 2 i :

No Solution

Combine all the solutions

No Solution for θ \in R

3 tan^{2} (θ) + 3 tan (θ) = 0, 0^{\circ} \leq θ \leq 36 0^{\circ}

cos (a) = \frac{24}{25}

sin^{2} (x) = 3 sin (x) - 2

4 sin^{2} (3 x) - 1 = 0

sin (θ) - 2 cos^{2} (θ) = - 1

What is the general solution for sin^2(θ)-2sin(θ)+3=0 ?
The general solution for sin^2(θ)-2sin(θ)+3=0 is No Solution for θ\in\mathbb{R}