What is the general solution for cos^2(150)-sin^2(150)=tan(x) ?

The general solution for cos^2(150)-sin^2(150)=tan(x) is x=0.46364…+180n

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cos^2(150)-sin^2(150)=tan(x)

cos^{2} (15 0^{\circ}) - sin^{2} (15 0^{\circ}) = tan (x)

x = 0.46364 \dots + 18 0^{\circ} n

Solution steps

cos^{2} (15 0^{\circ}) - sin^{2} (15 0^{\circ}) = tan (x)

cos (15 0^{\circ}) = - \frac{3}{2}

sin (15 0^{\circ}) = \frac{1}{2}

(- \frac{3}{2})^{2} - (\frac{1}{2})^{2} = tan (x)

Switch sides

tan (x) = (- \frac{3}{2})^{2} - (\frac{1}{2})^{2}

Simplify

(- \frac{3}{2})^{2} - (\frac{1}{2})^{2} : \frac{1}{2}

Apply trig inverse properties

x = arctan (\frac{1}{2}) + 18 0^{\circ} n

Show solutions in decimal form

x = 0.46364 \dots + 18 0^{\circ} n

3 - sin (x) = 0

lo g_{8} (4) = \frac{( sin ^{2} ( x ) )}{sin ( x ) - \frac{1}{8}}

4 \cdot cos^{2} (x) - 1 = 0

tan (2 x - 5) = sin^{2} (3 0^{\circ}) + sin^{2} (6 0^{\circ})

5 sin (x) (sin (x) - 1) = 0

What is the general solution for cos^2(150)-sin^2(150)=tan(x) ?
The general solution for cos^2(150)-sin^2(150)=tan(x) is x=0.46364…+180n