What is the general solution for 5sin(x)(sin(x)-1)=0 ?

The general solution for 5sin(x)(sin(x)-1)=0 is x=2pin,x=pi+2pin,x= pi/2+2pin

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5sin(x)(sin(x)-1)=0

5 sin (x) (sin (x) - 1) = 0

x = 2 πn, x = π + 2 πn, x = \frac{π}{2} + 2 πn

Solution steps

5 sin (x) (sin (x) - 1) = 0

Solving each part separately

sin (x) = 0 or sin (x) - 1 = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) - 1 = 0 : x = \frac{π}{2} + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{π}{2} + 2 πn

5 tan^{2} (x) - 9 sec (x) + 2 = 0

- sin (A) + 2 cos (A) sin (A) = 0

sin (2 θ) = - \frac{1}{2}, \forall 0 \leq θ < 2 π

t, 2 - 2 cosh (t - 2) = 0

3 tan (θ) = - 3, 0 \leq θ \leq 2 π

What is the general solution for 5sin(x)(sin(x)-1)=0 ?
The general solution for 5sin(x)(sin(x)-1)=0 is x=2pin,x=pi+2pin,x= pi/2+2pin