What is the general solution for tan(θ/2-pi/4)=1,0<= θ<2pi ?

The general solution for tan(θ/2-pi/4)=1,0<= θ<2pi is θ=pi

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tan(θ/2-pi/4)=1,0<= θ<2pi

tan (\frac{θ}{2} - \frac{π}{4}) = 1, 0 \leq θ < 2 π

θ = π

Solution steps

tan (\frac{θ}{2} - \frac{π}{4}) = 1, 0 \leq θ < 2 π

General solutions for

tan (\frac{θ}{2} - \frac{π}{4}) = 1

\frac{θ}{2} - \frac{π}{4} = \frac{π}{4} + πn

Solve

\frac{θ}{2} - \frac{π}{4} = \frac{π}{4} + πn : θ = π + 2 πn

θ = π + 2 πn

Solutions for the range

0 \leq θ < 2 π

θ = π

1 + cos^{2} (x^{2} + 1) = sin^{2} (x^{2} + 1)

2 sin^{2} (x) + sin (x) - 6 = 0

tan (θ) = \frac{8}{15}, sin (θ) > 0

cos (x) = \frac{86.6}{100}

- 2 cos^{2} (θ) - 8 cos (θ) - 1 = - 5 cos (θ)

What is the general solution for tan(θ/2-pi/4)=1,0<= θ<2pi ?
The general solution for tan(θ/2-pi/4)=1,0<= θ<2pi is θ=pi