What is the general solution for 5sec^2(x)-5=0,0<= x<= 2pi ?

The general solution for 5sec^2(x)-5=0,0<= x<= 2pi is x=0,x=2pi,x=pi

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5sec^2(x)-5=0,0<= x<= 2pi

5 sec^{2} (x) - 5 = 0, 0 \leq x \leq 2 π

x = 0, x = 2 π, x = π

Solution steps

5 sec^{2} (x) - 5 = 0, 0 \leq x \leq 2 π

Solve by substitution

sec (x) = 1, sec (x) = - 1

sec (x) = 1, 0 \leq x \leq 2 π : x = 0, x = 2 π

sec (x) = - 1, 0 \leq x \leq 2 π : x = π

Combine all the solutions

x = 0, x = 2 π, x = π

4 cos^{2} (θ) + 4 = 5

4 sin (2 z) - 3 cos (z) = 0

0.34 = cos (x)

7 sin (x) cos (x) + cos^{2} (x) = 1

(tan (x) - 1) (cos (x) - 1) = 0

What is the general solution for 5sec^2(x)-5=0,0<= x<= 2pi ?
The general solution for 5sec^2(x)-5=0,0<= x<= 2pi is x=0,x=2pi,x=pi