What is the general solution for (cos(30))/(cos(60))=tan(x) ?

The general solution for (cos(30))/(cos(60))=tan(x) is x=60+180n

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(cos(30))/(cos(60))=tan(x)

\frac{cos ( 3 0 ^{\circ} )}{cos ( 6 0 ^{\circ} )} = tan (x)

x = 6 0^{\circ} + 18 0^{\circ} n

Solution steps

\frac{cos ( 3 0 ^{\circ} )}{cos ( 6 0 ^{\circ} )} = tan (x)

cos (3 0^{\circ}) = \frac{3}{2}

cos (6 0^{\circ}) = \frac{1}{2}

\frac{\frac{3}{2}}{\frac{1}{2}} = tan (x)

Switch sides

tan (x) = \frac{\frac{3}{2}}{\frac{1}{2}}

Simplify

\frac{\frac{3}{2}}{\frac{1}{2}} : 3

General solutions for

tan (x) = 3

x = 6 0^{\circ} + 18 0^{\circ} n

4 cos^{2} (x) - 18 cos (x) - 10 = 0

25 sin (θ) - 1.5 cos (θ) = 20

sin (\frac{2 θ}{3}) = \frac{1}{2}, 0 \leq θ \leq 2 π

1 - sin^{2} (x) = e^{\frac{1}{2} l n (1 - c o s^{2} (x))}

cot^{2} (x) = tan (\frac{1}{2} x)

What is the general solution for (cos(30))/(cos(60))=tan(x) ?
The general solution for (cos(30))/(cos(60))=tan(x) is x=60+180n