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cos(x-pi/6)-sin(x)=0

解答

cos (x - \frac{π}{6}) - sin (x) = 0

解答

x = \frac{π}{3} + πn

+1

度数

x = 6 0^{\circ} + 18 0^{\circ} n

求解步骤

cos (x - \frac{π}{6}) - sin (x) = 0

使用三角恒等式改写

cos (x - \frac{π}{6}) - sin (x) = 0

使用三角恒等式改写

cos (x - \frac{π}{6})

使用角差恒等式:

cos (s - t) = cos (s) cos (t) + sin (s) sin (t)

= cos (x) cos (\frac{π}{6}) + sin (x) sin (\frac{π}{6})

化简

cos (x) cos (\frac{π}{6}) + sin (x) sin (\frac{π}{6}) : \frac{3}{2} cos (x) + \frac{1}{2} sin (x)

cos (x) cos (\frac{π}{6}) + sin (x) sin (\frac{π}{6})

化简

cos (\frac{π}{6}) : \frac{3}{2}

cos (\frac{π}{6})

使用以下普通恒等式:

cos (\frac{π}{6}) = \frac{3}{2}

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{3}{2}

= \frac{3}{2} cos (x) + sin (\frac{π}{6}) sin (x)

化简

sin (\frac{π}{6}) : \frac{1}{2}

sin (\frac{π}{6})

使用以下普通恒等式:

sin (\frac{π}{6}) = \frac{1}{2}

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

= \frac{3}{2} cos (x) + \frac{1}{2} sin (x)

= \frac{3}{2} cos (x) + \frac{1}{2} sin (x)

\frac{3}{2} cos (x) + \frac{1}{2} sin (x) - sin (x) = 0

化简

\frac{3}{2} cos (x) + \frac{1}{2} sin (x) - sin (x) : \frac{3}{2} cos (x) - \frac{1}{2} sin (x)

\frac{3}{2} cos (x) + \frac{1}{2} sin (x) - sin (x)

同类项相加:

\frac{1}{2} sin (x) - sin (x) = - \frac{1}{2} sin (x)

\frac{1}{2} sin (x) - sin (x)

因式分解出通项

sin (x)

= sin (x) (\frac{1}{2} - 1)

\frac{1}{2} - 1 = - \frac{1}{2}

\frac{1}{2} - 1

将项转换为分式:

1 = \frac{1 \cdot 2}{2}

= \frac{1}{2} - \frac{1 \cdot 2}{2}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 - 1 \cdot 2}{2}

1 - 1 \cdot 2 = - 1

1 - 1 \cdot 2

数字相乘:

1 \cdot 2 = 2

= 1 - 2

数字相减:

1 - 2 = - 1

= - 1

= \frac{- 1}{2}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{2}

= - \frac{1}{2} sin (x)

= \frac{3}{2} cos (x) - \frac{1}{2} sin (x)

\frac{3}{2} cos (x) - \frac{1}{2} sin (x) = 0

\frac{3}{2} cos (x) - \frac{1}{2} sin (x) = 0

化简

\frac{3}{2} cos (x) - \frac{1}{2} sin (x) : \frac{3 cos ( x ) - sin ( x )}{2}

\frac{3}{2} cos (x) - \frac{1}{2} sin (x)

\frac{3}{2} cos (x) = \frac{3 cos ( x )}{2}

\frac{3}{2} cos (x)

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 cos ( x )}{2}

\frac{1}{2} sin (x) = \frac{sin ( x )}{2}

\frac{1}{2} sin (x)

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot sin ( x )}{2}

乘以:

1 \cdot sin (x) = sin (x)

= \frac{sin ( x )}{2}

= \frac{3 cos ( x )}{2} - \frac{sin ( x )}{2}

使用法则

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 cos ( x ) - sin ( x )}{2}

\frac{3 cos ( x ) - sin ( x )}{2} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

3 cos (x) - sin (x) = 0

使用三角恒等式改写

3 cos (x) - sin (x) = 0

在两边除以

cos (x), cos (x) \neq = 0

\frac{3 cos ( x ) - sin ( x )}{cos ( x )} = \frac{0}{cos ( x )}

化简

3 - \frac{sin ( x )}{cos ( x )} = 0

使用基本三角恒等式:

\frac{sin ( x )}{cos ( x )} = tan (x)

3 - tan (x) = 0

3 - tan (x) = 0

将

3

到右边

3 - tan (x) = 0

两边减去

3

3 - tan (x) - 3 = 0 - 3

化简

- tan (x) = - 3

- tan (x) = - 3

两边除以

- 1

- tan (x) = - 3

两边除以

- 1

\frac{- tan ( x )}{- 1} = \frac{- 3}{- 1}

化简

tan (x) = 3

tan (x) = 3

tan (x) = 3

的通解

tan (x)

周期表（周期为

πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{3} + πn

x = \frac{π}{3} + πn

流行的例子

2+cos^2(x)=-3cos(x)

2 + cos^{2} (x) = - 3 cos (x)

6sec^2(x)+tan(x)-7=0

6 sec^{2} (x) + tan (x) - 7 = 0

4 \cdot sin^{2} (x) = 3

cos (B) = \frac{2}{3}

tan(θ)sin(θ)=3sin(θ)

tan (θ) sin (θ) = 3 sin (θ)