What is the general solution for sin((2θ)/3)= 1/2 ,0<= θ<= 2pi ?

The general solution for sin((2θ)/3)= 1/2 ,0<= θ<= 2pi is θ= pi/4 ,θ=(5pi)/4

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sin((2θ)/3)= 1/2 ,0<= θ<= 2pi

sin (\frac{2 θ}{3}) = \frac{1}{2}, 0 \leq θ \leq 2 π

θ = \frac{π}{4}, θ = \frac{5 π}{4}

Solution steps

sin (\frac{2 θ}{3}) = \frac{1}{2}, 0 \leq θ \leq 2 π

General solutions for

sin (\frac{2 θ}{3}) = \frac{1}{2}

\frac{2 θ}{3} = \frac{π}{6} + 2 πn, \frac{2 θ}{3} = \frac{5 π}{6} + 2 πn

Solve

\frac{2 θ}{3} = \frac{π}{6} + 2 πn : θ = \frac{π}{4} + 3 πn

Solve

\frac{2 θ}{3} = \frac{5 π}{6} + 2 πn : θ = \frac{5 π}{4} + 3 πn

θ = \frac{π}{4} + 3 πn, θ = \frac{5 π}{4} + 3 πn

Solutions for the range

0 \leq θ \leq 2 π

θ = \frac{π}{4}, θ = \frac{5 π}{4}

1 - sin^{2} (x) = e^{\frac{1}{2} l n (1 - c o s^{2} (x))}

cot^{2} (x) = tan (\frac{1}{2} x)

cos (C) = \frac{3}{4}

cos (x - \frac{π}{6}) - sin (x) = 0

2 + cos^{2} (x) = - 3 cos (x)

What is the general solution for sin((2θ)/3)= 1/2 ,0<= θ<= 2pi ?
The general solution for sin((2θ)/3)= 1/2 ,0<= θ<= 2pi is θ= pi/4 ,θ=(5pi)/4