What is the general solution for 2sin^2(θ)-2=3sin(θ) ?

The general solution for 2sin^2(θ)-2=3sin(θ) is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin

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2sin^2(θ)-2=3sin(θ)

2 sin^{2} (θ) - 2 = 3 sin (θ)

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Solution steps

2 sin^{2} (θ) - 2 = 3 sin (θ)

Solve by substitution

sin (θ) = 2, sin (θ) = - \frac{1}{2}

sin (θ) = 2 :

No Solution

sin (θ) = - \frac{1}{2} : θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Combine all the solutions

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

4 sin^{2} (x) - 7 sin (x) + 3 = 0

2 sin (x - 1 0^{\circ}) = - 0.4

cot^{2} (2 x - \frac{π}{3}) = \frac{1}{3}

sin (2 x) = 0.8, - 18 0^{\circ} \leq x \leq 18 0^{\circ}

\frac{tan ( x )}{1 + tan ( x )} = 0

What is the general solution for 2sin^2(θ)-2=3sin(θ) ?
The general solution for 2sin^2(θ)-2=3sin(θ) is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin