What is the general solution for (12000}{2*6380}=tan(\frac{90-u)/2) ?

The general solution for (12000}{2*6380}=tan(\frac{90-u)/2) is u=-360n+90-2*0.75471…

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(12000}{2*6380}=tan(\frac{90-u)/2)

\frac{12000}{2 \cdot 6380} = tan (\frac{9 0 ^{\circ} - u}{2})

u = - 36 0^{\circ} n + 9 0^{\circ} - 2 \cdot 0.75471 \dots

Solution steps

\frac{12000}{2 \cdot 6380} = tan (\frac{9 0 ^{\circ} - u}{2})

Switch sides

tan (\frac{9 0 ^{\circ} - u}{2}) = \frac{12000}{2 \cdot 6380}

Simplify

\frac{12000}{2 \cdot 6380} : \frac{300}{319}

Apply trig inverse properties

\frac{9 0 ^{\circ} - u}{2} = arctan (\frac{300}{319}) + 18 0^{\circ} n

Solve

\frac{9 0 ^{\circ} - u}{2} = arctan (\frac{300}{319}) + 18 0^{\circ} n : u = - 36 0^{\circ} n + 9 0^{\circ} - 2 arctan (\frac{300}{319})

u = - 36 0^{\circ} n + 9 0^{\circ} - 2 arctan (\frac{300}{319})

Show solutions in decimal form

u = - 36 0^{\circ} n + 9 0^{\circ} - 2 \cdot 0.75471 \dots

cos^{2} (t) - 3 sin (t) = 3

4 sin^{4} (x) - 4 sin^{2} (x) + 1 = 0

4 sin (θ) + 23 = 0, 0^{\circ} \leq θ \leq 36 0^{\circ}

(1.33) sin (2 5^{\circ}) = (1.5) sin (θ)

cos (y) = - \frac{1}{2}

What is the general solution for (12000}{2*6380}=tan(\frac{90-u)/2) ?
The general solution for (12000}{2*6380}=tan(\frac{90-u)/2) is u=-360n+90-2*0.75471…