What is the general solution for 4sin(θ)+2sqrt(3)=0,0<= θ<= 360 ?

The general solution for 4sin(θ)+2sqrt(3)=0,0<= θ<= 360 is θ=240,θ=300

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4sin(θ)+2sqrt(3)=0,0<= θ<= 360

4 sin (θ) + 23 = 0, 0^{\circ} \leq θ \leq 36 0^{\circ}

θ = 24 0^{\circ}, θ = 30 0^{\circ}

Solution steps

4 sin (θ) + 23 = 0, 0^{\circ} \leq θ \leq 36 0^{\circ}

Move

23

to the right side

4 sin (θ) = - 23

Divide both sides by

4

sin (θ) = - \frac{3}{2}

General solutions for

sin (θ) = - \frac{3}{2}

θ = 24 0^{\circ} + 36 0^{\circ} n, θ = 30 0^{\circ} + 36 0^{\circ} n

Solutions for the range

0 \leq θ \leq 36 0^{\circ}

θ = 24 0^{\circ}, θ = 30 0^{\circ}

(1.33) sin (2 5^{\circ}) = (1.5) sin (θ)

cos (y) = - \frac{1}{2}

\frac{2}{1 + sin ( x )} = 3 - 2 sin (x)

x, 4 cos^{2} (x) = 5 + 4 sin (x)

t, y = cos (2 t)

What is the general solution for 4sin(θ)+2sqrt(3)=0,0<= θ<= 360 ?
The general solution for 4sin(θ)+2sqrt(3)=0,0<= θ<= 360 is θ=240,θ=300