What is the general solution for cos(θ-pi/6)=(sqrt(3))/2 ?

The general solution for cos(θ-pi/6)=(sqrt(3))/2 is θ= pi/3+2pin,θ=2pin+2pi

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cos(θ-pi/6)=(sqrt(3))/2

cos (θ - \frac{π}{6}) = \frac{3}{2}

θ = \frac{π}{3} + 2 πn, θ = 2 πn + 2 π

Solution steps

cos (θ - \frac{π}{6}) = \frac{3}{2}

General solutions for

cos (θ - \frac{π}{6}) = \frac{3}{2}

θ - \frac{π}{6} = \frac{π}{6} + 2 πn, θ - \frac{π}{6} = \frac{11 π}{6} + 2 πn

Solve

θ - \frac{π}{6} = \frac{π}{6} + 2 πn : θ = \frac{π}{3} + 2 πn

Solve

θ - \frac{π}{6} = \frac{11 π}{6} + 2 πn : θ = 2 πn + 2 π

θ = \frac{π}{3} + 2 πn, θ = 2 πn + 2 π

csc (θ) = - \frac{5}{3}

2 sin^{2} (t) cos (t) = 0

2 cos (θ) + sin (θ) = 0

2 sin^{2} (x) + sin (x) - 1 = 0, 0 < x < 2 π

5 sin (x) - 12 cos (x) = 13

What is the general solution for cos(θ-pi/6)=(sqrt(3))/2 ?
The general solution for cos(θ-pi/6)=(sqrt(3))/2 is θ= pi/3+2pin,θ=2pin+2pi