What is the general solution for 4tan(x)+1=0 ?

The general solution for 4tan(x)+1=0 is x=-0.24497…+pin

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4tan(x)+1=0

4 tan (x) + 1 = 0

x = - 0.24497 \dots + πn

Degrees

x = - 14.03624 \dots^{\circ} + 18 0^{\circ} n

Solution steps

4 tan (x) + 1 = 0

Move

1

to the right side

4 tan (x) + 1 = 0

Subtract

1

from both sides

4 tan (x) + 1 - 1 = 0 - 1

Simplify

4 tan (x) = - 1

4 tan (x) = - 1

Divide both sides by

4

4 tan (x) = - 1

Divide both sides by

4

\frac{4 tan ( x )}{4} = \frac{- 1}{4}

Simplify

tan (x) = - \frac{1}{4}

tan (x) = - \frac{1}{4}

Apply trig inverse properties

tan (x) = - \frac{1}{4}

General solutions for

tan (x) = - \frac{1}{4}

tan (x) = - a \Rightarrow x = arctan (- a) + πn

x = arctan (- \frac{1}{4}) + πn

x = arctan (- \frac{1}{4}) + πn

Show solutions in decimal form

x = - 0.24497 \dots + πn

3 tan (θ) - 4 = tan (θ) - 2

sinh (- x) = sinh (x)

cot^{2} (θ) = - cot (θ)

sin (x) = \frac{- 4}{7}

1 - cos (θ) = \frac{2 π}{3}

What is the general solution for 4tan(x)+1=0 ?
The general solution for 4tan(x)+1=0 is x=-0.24497…+pin