What is the general solution for sin(2x)-(sqrt(2))/2 =0 ?

The general solution for sin(2x)-(sqrt(2))/2 =0 is x= pi/8+pin,x=(3pi)/8+pin

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sin(2x)-(sqrt(2))/2 =0

sin (2 x) - \frac{2}{2} = 0

x = \frac{π}{8} + πn, x = \frac{3 π}{8} + πn

Solution steps

sin (2 x) - \frac{2}{2} = 0

Move

\frac{2}{2}

to the right side

sin (2 x) = \frac{2}{2}

General solutions for

sin (2 x) = \frac{2}{2}

2 x = \frac{π}{4} + 2 πn, 2 x = \frac{3 π}{4} + 2 πn

Solve

2 x = \frac{π}{4} + 2 πn : x = \frac{π}{8} + πn

Solve

2 x = \frac{3 π}{4} + 2 πn : x = \frac{3 π}{8} + πn

x = \frac{π}{8} + πn, x = \frac{3 π}{8} + πn

y, z = x sin (x y)

sin (θ) = 0.12

cos (x) tan (x) - sin^{2} (x) = 0

t, y^{11} + 9 y = 18 cos (3 t)

tan (x) = \frac{0.75}{6}

What is the general solution for sin(2x)-(sqrt(2))/2 =0 ?
The general solution for sin(2x)-(sqrt(2))/2 =0 is x= pi/8+pin,x=(3pi)/8+pin