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Popular >

sin(x)+sin^2(x)+sin^3(x)+sin^4(x)=0

Solution

sin (x) + sin^{2} (x) + sin^{3} (x) + sin^{4} (x) = 0

Solution

x = 2 πn, x = π + 2 πn, x = \frac{3 π}{2} + 2 πn

+1

Solution steps

sin (x) + sin^{2} (x) + sin^{3} (x) + sin^{4} (x) = 0

Solve by substitution

sin (x) = 0, sin (x) = - 1, sin (x) = i, sin (x) = - i

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

sin (x) = i :

No Solution

sin (x) = - i :

No Solution

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{3 π}{2} + 2 πn

Popular Examples

sin(9x)-cos(x)=0

sin (9 x) - cos (x) = 0

cos(x)+2cos^2(x)=1

cos (x) + 2 cos^{2} (x) = 1

solvefor t,0.08=0.1cos(4t)solve for

t, 0.08 = 0.1 cos (4 t)

- \frac{2}{3} = cos (x)

solvefor ϕ,(xcos(ϕ))^2=x^2sin^2(ϕ)(1)solve for

ϕ, (x cos (ϕ))^{2} = x^{2} sin^{2} (ϕ) (1)

Frequently Asked Questions (FAQ)

What is the general solution for sin(x)+sin^2(x)+sin^3(x)+sin^4(x)=0 ?
The general solution for sin(x)+sin^2(x)+sin^3(x)+sin^4(x)=0 is x=2pin,x=pi+2pin,x=(3pi)/2+2pin