What is the general solution for cos(x)*sin(x)-2cos(x)=0 ?

The general solution for cos(x)*sin(x)-2cos(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin

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cos(x)*sin(x)-2cos(x)=0

cos (x) \cdot sin (x) - 2 cos (x) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

cos (x) sin (x) - 2 cos (x) = 0

Factor

cos (x) sin (x) - 2 cos (x) : cos (x) (sin (x) - 2)

cos (x) (sin (x) - 2) = 0

Solving each part separately

cos (x) = 0 or sin (x) - 2 = 0

cos (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

sin (x) - 2 = 0 :

No Solution

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

sec (4 x) - \frac{2}{3} = 0

cos (θ) = 0.3, cos (2 θ)

(- \frac{2}{3})^{2} + 1 = sec (θ)

1 = sech^{2} (x)

tan (θ) = 0.86667

What is the general solution for cos(x)*sin(x)-2cos(x)=0 ?
The general solution for cos(x)*sin(x)-2cos(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin