What is the general solution for sin^2(θ)+cos(θ)-cos^2(θ)=0 ?

The general solution for sin^2(θ)+cos(θ)-cos^2(θ)=0 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin,θ=2pin

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sin^2(θ)+cos(θ)-cos^2(θ)=0

sin^{2} (θ) + cos (θ) - cos^{2} (θ) = 0

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn, θ = 2 πn

Solution steps

sin^{2} (θ) + cos (θ) - cos^{2} (θ) = 0

Rewrite using trig identities

1 + cos (θ) - 2 cos^{2} (θ) = 0

Solve by substitution

cos (θ) = - \frac{1}{2}, cos (θ) = 1

cos (θ) = - \frac{1}{2} : θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

cos (θ) = 1 : θ = 2 πn

Combine all the solutions

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn, θ = 2 πn

\frac{cos ( x )}{sin ( 2 x )} = \frac{5}{7}

tan (x) = \frac{6 \cdot 0.809}{15}

tan (θ) = \frac{8}{20}

cos^{2} (x) = \frac{( 5 k - 8 )}{5}

3 arcsin (x) = \frac{π}{2}

What is the general solution for sin^2(θ)+cos(θ)-cos^2(θ)=0 ?
The general solution for sin^2(θ)+cos(θ)-cos^2(θ)=0 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin,θ=2pin