What is the general solution for (sin(x))^2+(1-sqrt(2))sin(x)-sqrt(2)=0 ?

The general solution for (sin(x))^2+(1-sqrt(2))sin(x)-sqrt(2)=0 is x=(3pi)/2+2pin

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(sin(x))^2+(1-sqrt(2))sin(x)-sqrt(2)=0

(sin (x))^{2} + (1 - 2) sin (x) - 2 = 0

x = \frac{3 π}{2} + 2 πn

Solution steps

(sin (x))^{2} + (1 - 2) sin (x) - 2 = 0

Solve by substitution

sin (x) = 2, sin (x) = - 1

sin (x) = 2 :

No Solution

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{3 π}{2} + 2 πn

4 sin^{2} (A) - 1 = 0

tan (θ) = \frac{22}{7}

u, x = 4 tanh (u)

tan (x) = \frac{2}{7}

sin^{2} (θ) + cos (θ) - cos^{2} (θ) = 0

What is the general solution for (sin(x))^2+(1-sqrt(2))sin(x)-sqrt(2)=0 ?
The general solution for (sin(x))^2+(1-sqrt(2))sin(x)-sqrt(2)=0 is x=(3pi)/2+2pin