What is the general solution for 1/(sqrt(2))=cos(θ) ?

The general solution for 1/(sqrt(2))=cos(θ) is θ= pi/4+2pin,θ=(7pi)/4+2pin

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1/(sqrt(2))=cos(θ)

\frac{1}{2} = cos (θ)

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

Solution steps

\frac{1}{2} = cos (θ)

Switch sides

cos (θ) = \frac{1}{2}

Simplify

\frac{1}{2} : \frac{2}{2}

General solutions for

cos (θ) = \frac{2}{2}

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

tan^{2} (x) + 5 tan (x) = 0

1 - sinh^{2} (x) = 0

sin (y + 1 0^{\circ}) = cos (y + 2 0^{\circ})

tan (x) = - 1, 7

tan (θ) (3 cos^{2} (θ) - sin^{2} (θ)) = 0

What is the general solution for 1/(sqrt(2))=cos(θ) ?
The general solution for 1/(sqrt(2))=cos(θ) is θ= pi/4+2pin,θ=(7pi)/4+2pin