What is the general solution for -3-5/2*cos(θ)=-3-3cos(θ) ?

The general solution for -3-5/2*cos(θ)=-3-3cos(θ) is θ= pi/2+2pin,θ=(3pi)/2+2pin

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-3-5/2*cos(θ)=-3-3cos(θ)

- 3 - \frac{5}{2} \cdot cos (θ) = - 3 - 3 cos (θ)

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

- 3 - \frac{5}{2} cos (θ) = - 3 - 3 cos (θ)

Solve by substitution

cos (θ) = 0

cos (θ) = 0 : θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

tan (θ) = - \frac{6}{5}

3 sec (2 θ) = - 18

2 sin^{2} (x) - 2 = cos^{2} (x)

sin (2 θ) = \frac{1}{3}

cos^{2} (θ) = 1 - sin (θ)

What is the general solution for -3-5/2*cos(θ)=-3-3cos(θ) ?
The general solution for -3-5/2*cos(θ)=-3-3cos(θ) is θ= pi/2+2pin,θ=(3pi)/2+2pin