What is the general solution for solvefor u,x=sinh(u) ?

The general solution for solvefor u,x=sinh(u) is u=ln(x+sqrt(x^2+1)),u=ln(x-sqrt(x^2+1))

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solvefor u,x=sinh(u)

solve for

u, x = sinh (u)

u = ln (x + x^{2} + 1), u = ln (x - x^{2} + 1)

Solution steps

x = sinh (u)

Switch sides

sinh (u) = x

Rewrite using trig identities

\frac{e ^{u} - e ^{- u}}{2} = x

\frac{e ^{u} - e ^{- u}}{2} = x : u = ln (x + x^{2} + 1), u = ln (x - x^{2} + 1)

u = ln (x + x^{2} + 1), u = ln (x - x^{2} + 1)

sin (θ) = \frac{tan ( θ )}{sin ( θ )}

5 tan^{2} (t) - tan (t) = 0

sin (x) = \frac{9}{16}

24 = 32 + 8 - 2 \cdot 32 \cdot 8 \cdot cos (θ)

sin (4 5^{\circ} + a) cos (4 5^{\circ} + a) = \frac{2}{2}

What is the general solution for solvefor u,x=sinh(u) ?
The general solution for solvefor u,x=sinh(u) is u=ln(x+sqrt(x^2+1)),u=ln(x-sqrt(x^2+1))