What is the general solution for cos^2(x)+2cos(x)+1=0,(0,2pi) ?

The general solution for cos^2(x)+2cos(x)+1=0,(0,2pi) is x=pi

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cos^2(x)+2cos(x)+1=0,(0,2pi)

cos^{2} (x) + 2 cos (x) + 1 = 0, (0, 2 π)

x = π

Solution steps

cos^{2} (x) + 2 cos (x) + 1 = 0, (0, 2 π)

Solve by substitution

cos (x) = - 1

cos (x) = - 1, (0, 2 π) : x = π

Combine all the solutions

x = π

3 sin (2 θ) = 2 sin (θ)

sin (x) \cdot cos^{2} (x) = sin (x)

sinh (y) = - 2

2 sin (θ) = - 3 + 4 sin (θ)

7^{2} = 6^{2} + 1 1^{2} - 2 \cdot 6 \cdot 11 \cdot cos (D)

What is the general solution for cos^2(x)+2cos(x)+1=0,(0,2pi) ?
The general solution for cos^2(x)+2cos(x)+1=0,(0,2pi) is x=pi