What is the general solution for 112=72+40cos(18t) ?

The general solution for 112=72+40cos(18t) is t=(pin)/9

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112=72+40cos(18t)

112 = 72 + 40 cos (18 t)

t = \frac{πn}{9}

Solution steps

112 = 72 + 40 cos (18 t)

Switch sides

72 + 40 cos (18 t) = 112

Move

72

to the right side

40 cos (18 t) = 40

Divide both sides by

40

cos (18 t) = 1

General solutions for

cos (18 t) = 1

18 t = 0 + 2 πn

Solve

18 t = 0 + 2 πn : t = \frac{πn}{9}

t = \frac{πn}{9}

1 + sin (x) = (2) (cos (x))

cos (2 x) = - 0.32

sin (\frac{3 π}{2} - 0) = - cos (x)

sec (x) = - \frac{7}{4}

28 cos^{2} (θ) = 7

What is the general solution for 112=72+40cos(18t) ?
The general solution for 112=72+40cos(18t) is t=(pin)/9